Answer:
x = 1 , y = 1
Explanation:
Solve the following system:
{2 x + y = 3 | (equation 1)
x = 2 y - 1 | (equation 2)
Express the system in standard form:
{2 x + y = 3 | (equation 1)
x - 2 y = -1 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 3 | (equation 1)
0 x - (5 y)/2 = (-5)/2 | (equation 2)
Multiply equation 2 by -2/5:
{2 x + y = 3 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 2 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 1 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 1 , y = 1