Question

A cash register contains 10$ bills and 20$ bills total value of 340 if there are 23 bills total then how many of each does the register contains

Answer 1

There are 12 bills of 10$ and 11 bills of 20$

Explanation:

Let

x ------> number of 10$ bills

y -----> number of 20$ bills

we know that

x+y=23 -----> x=23-y -----> equation A

10x+20y=340 ----> equation B

substitute equation A in equation B and solve for y

10(23-y)+20y=340

230-10y+20y=340

10y=340-230

y=110/10=11

Find the value of x

x=23-y ----> x=23-11=12

therefore

There are 12 bills of 10$ and 11 bills of 20$