Answer: The solution to the system of equations y = x² - 2x - 15 and y = 8x - 40 is (5,0).
Explanation: Substitute y = 8x - 40 in y = x² - 2x - 15
8x - 40 = x² - 2x - 15
Identify the like terms
x² - 2x - 8x - 15 + 40 = 0
Evaluate the equation
x² - 10x + 25 = 0
Factorize the equation
(x - 5)(x - 5) = 0
Solve for x
x - 5 = 0 and x - 5 = 0
Solving for x gives
x = 5
Substitute x = 5 in y = 8x - 40
y = 8(5) - 40
y = 0