Question

Select the correct answer from each drop-down menu.

A 126.1-gram block of granite at 92.6°C is dropped into a tub of water at 24.7°C in an isolated system. The final temperature of both the granite and the water is 51.9°C. The specific heat capacity of granite is 0.795 joules/gram degree Celsius, and the specific heat capacity of water is 4.186 joules/gram degree Celsius.

The granite block transferred ______
C of energy, and the mass of the water is_____

Answer 1

Answer: blank 1: 4,080 joules

Blank 2: 35.8 grams

Step-by-step explanation:

Answer 2

The granite block transferred 4080 joules of energy, and the mass of the water is 35.84 grams.

Step-by-step explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

Part #1:

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J c = 0.795 J/g°C

m = 126.1 g ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

Part #2:

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J c = 4.186 J/g°C

m = ? g ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m