Question

An object was measured by a worker as

14.6cm long, however, the manufacturer
specifications list the length of the object at
14.4cm. What is the percent error in the
worker's measurement?

Answer 1

Answer - 0.73%

14.6 .2

=

100 x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

Answer 2

Answer: The percent error in the worker's measurement is 1.38%

Explanation:

Actual length of the object = 14.4 cm

length measured by the worker = 14.6 cm

absolute error in measuring the object = 14.6 - 14. 4 = 0.2 cm

percentage error =
`\frac{\text {absolute error}}{\text {actual length}}* 100\%`

Putting in the values we get:

percentage error =
`(0.2)/(14.4)* 100\%=1.38\%`

Thus the percent error in the worker's measurement is 1.38%