163k views
2 votes
What is the rate of change and initial value for Neil’s business and write and equeation for it

What is the rate of change and initial value for Neil’s business and write and equeation-example-1
User Nandish A
by
5.4k points

2 Answers

6 votes
It is 1/8 divided by 8
User RishiKesh Pathak
by
5.4k points
7 votes

Answer: $50 per year, y = 50x + 1200

Explanation:

The rate of change is the slope of the two coordinates (0, 1200) & (3, 1350). Note that 2005 is represented as 0 years since the company started and 2008 represents 3 years since the company started.

Use the slope formula:
(y_2-y_1)/(x_2-x_1) = (1350-1200)/(3-0)=(150)/(3)=\$50 \text{ per year}

To write the equation in slope-intercept form, input a point (x₁, y₁) and the slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y

y - 1200 = 50(x - 0)

y - 1200 = 50x

y = 50x + 1200 ; where x represents the number of years the

company has been in business.

User Mar De Romos
by
5.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.