Answer:
The function whose graph is given below is:
A)

Explanation:
From the graph that is provided to us we observe that,
when x=2
then f(x)=1
Hence, we will check which function satisfies this point.
B)

At x=2 we have:

Hence, option: B is incorrect.
C)

when x=2 we have:

Hence, option: C is incorrect.
D)

when x=2 we have:

Hence, option: D is incorrect.
So, we are left with option: A
A)

when x=2
we get: y=1
Similarly all the other points are satisfied.
Also, the graph of this function matches the given graph.