Question

A motor with an operating resistance of 2.21 ohms is connected to a voltage source. The current in the circuit is 3.8 A and the power of the system is 32 watts. What is the voltage of the source?

Answer 1

Hello!

The answer is:

The voltage of the source is 8.40 Volts.

Why?

To solve the problem, we need to use the Ohm's Law equation, which states that:

`Voltage(Volts)=Current(Amps)*Resistance(Ohm)`

From the statement we know that:

`Resistance=2.21\Omega\\Power=32W\\Current=3.8A`

Now, substituting and calculating we have:

`Voltage(Volts)=Current(Amps)*Resistance(Ohm)`

`Voltage(Volts)=3.8A*2.21\Omega=8.40V`

Hence, we have that the voltage of the source is 8.40 Volts.

Have a nice day!