Question

A motor with an operating resistance of 2.21 ohms is connected to a voltage source. The current in the circuit is 3.8 A and the power of the system is 32 watts. What is the voltage of the source?

Answer 1

Hello!

The answer is:

The voltage of the source is 8.40 Volts.

Why?

To solve the problem, we need to use the Ohm's Law equation base formula.

We have that we can calculate the voltage using the following equation:

`Voltage(Volts)=Current(Amps)*Resistance(Ohm)`

So, from the statement we know that:

`Resistance=2.21\Omega\\Power=32W\\Current=3.8A`

Now, substituting and calculating we have:

`Voltage(Volts)=Current(Amps)*Resistance(Ohm)`

`Voltage(Volts)=3.8A*2.21\Omega=8.40V`

Hence, we have that the voltage of the source is 8.40 Volts.

Have a nice day!