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Solve for x in the equation y^2 + 2x + 1 = 17.


Solve for x in the equation y^2 + 2x + 1 = 17. ​-example-1
User Dunston
by
8.1k points

2 Answers

1 vote

Answer:

B

Explanation:

So your equation is actually x^2+2x+1=17

Left hand side is already set for rewriting it as a perfect square

So you have actually that (x+1)^2=17

Now you just take square root of both sides

x+1=(pm) sqrt(17) (pm) means plus or minus

x=-1 (pm) sqrt(17) I subtracted 1 on both sides

B

User Mounesh
by
8.4k points
7 votes

Answer:

x = −1 ± √17

Hope this helps and have a nice day! :)

User Vikash Dat
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8.4k points