Question

An object was measured by a worker as

17.4cm long, however, the manufacturer
specifications list the length of the object at
17.9cm. What is the percent error in the
workers measurement?

Answer 1

`\boxed{2.8 \, \%}`

Step-by-step explanation:

`\text{Percent error} = \frac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} *100 \, \%`

Data:

Predicted = 17.4 cm

Actual = 17.9 cm

Calculation:

`\text{Percent error} = (\lvert 17.4 - 17.9\lvert)/(17.9) * 100 \, \% \\\\= (\lvert-0.5\lvert)/(17.9) * 100 \, \% = (0.5)/(17.9) * 100 \, \% \\\\= 0.028 * 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}`