Answer:
k∈(-∞;-3]∪[2;+∞).
Explanation:
step 1) if 2k+1>0, then
2k+1≥5; ⇔ k≥2;
step 2) if 2k+1<0, then
2k+1≤-5; ⇔ k≤-3;
step 3) finally, k∈(-∝;-3]∪[2;+∞).
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