196k views
0 votes
Solve the following system of equations

3x - 2y =55

-2x - 3y = 14

User Giangimgs
by
5.8k points

2 Answers

2 votes

Answer:

x = 411/39 and y = -152/13

Explanation:

It is given that,

3x - 2y = 55 ----(1)

-2x - 3y = 14 ---(2)

To find the solution of given equations

eq(1) * 2 ⇒

6x - 4y = 110 ---(3)

eq(2) * 3 ⇒

-6x - 9y = 42 ---(4)

eq(3) + eq(4) ⇒

6x - 4y = 110 ---(3)

-6x - 9y = 42 ---(4)

0 - 13y = 152

y = -152/13

Substitute the value of y in eq (1)

3x - 2y = 55 ----(1)

3x - 2*(-152/13) = 55

3x + 304/13 = 55

3x = 411/13

x = 411/39

Therefore x = 411/39 and y = -152/13

User Thomas Shields
by
5.4k points
6 votes

Answer:

The solution is:


((137)/(13), -(152)/(13))

Explanation:

We have the following equations


3x - 2y =55


-2x - 3y = 14

To solve the system multiply by
(3)/(2) the second equation and add it to the first equation


-2*(3)/(2)x - 3(3)/(2)y = 14(3)/(2)


-3x - (9)/(2)y = 21


3x - 2y =55

---------------------------------------


-(13)/(2)y=76


y=-76*(2)/(13)


y=-(152)/(13)

Now substitute the value of y in any of the two equations and solve for x


-2x - 3(-(152)/(13)) = 14


-2x +(456)/(13) = 14


-2x= 14-(456)/(13)


-2x=-(274)/(13)


x=(137)/(13)

The solution is:


((137)/(13), -(152)/(13))

User Fgp
by
5.5k points