1 Answer

Scott Buchanan · Answer 1 · 2020-08-24T21:34:13+0000

Answer:

$\large\boxed{y=2x^2+4}$

Explanation:

The vertex form of a parabola:

y=a(x-h)^2+k

(h, k) - vertex

We have the vertex at (0, 4) → h = 0 and k = 4.

Substitute:

y=a(x-0)^2+4=ax^2+4

The point (-1, 6) is on the parabola. Put the coordinates of the point to the equation:

6=a(-1)^2+4 subtract 4 from both sides

$2=a\to a=2$

Finally:

y=2x^2+4

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