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Use the definition of continuity to determine whether f is continuous at a. f(x) = 5x4 - 9x3 + x - 7a = 7

User Ian Viney
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We have
f(7)=8918. By the definition of continuity, we require that


\displaystyle\lim_(x\to7)f(x)=f(7)

So for any
\varepsilon>0, we want to find sufficient
\delta for which


0<|x-7|<\delta\implies|f(x)-8918|<\varepsilon

We have


|5x^4-9x^3+x-7-8918|=|5 x^4 - 9 x^3 + x - 8925|=|x - 7||5 x^3 + 26 x^2 + 182 x + 1275|

Suppose we let
0<\delta\le1. Then


|x-7|\le1\implies x\le8

so that


|5 x^3 + 26 x^2 + 182 x + 1275|\le5|x|^3+26|x|^2+182|x|+1275\le6955


\implies|5x^4-9x^3+x-7-8918|\le6955|x-7|<\varepsilon


\implies|x-7|<\frac\varepsilon{6955}

which suggests that it suffices to choose


\delta=\min\left\{1,\frac\varepsilon{6955}\right\}

in order to meet the required condition.

User Steven Licht
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