Question

In a much smaller model of the Gizmo apparatus, a 5 kg mass drops 86 mm (0.086 m) and raises the temperature of 1 gram of water 1°C. How much energy was transferred to the water? (Use a value of 9.8 m/s2 for g.)

Answer 1

The amount of energy transferred to the water is E = 4.214 [J]

Step-by-step explanation:

The energy that was transferred to the water was originally found as potential energy, when the mass falls the distance of 86 mm, this energy is converted to kinetic energy and at the moment of falling into the water it is converted from kinetic energy to thermal.

`E_(pot)=E_(kin)\\E_(pot)=m*g*h`

where:

m = mass = 5 [kg]

g = gravity = 9.8 [m/s²]

h = elevation = 86 [mm] = 0.086 [m]

`E_(pot)=5*9.8*0.086\\E_(pot)=4.214[J]`