Question

a car travels 1.2 miles from point a to point b. the car then turns at point b and travels 1.8 miles to point c before heading back to point a. the distance from point point c to point a is 1.6 miles. if the cars path is represented by a triangle what angle turn

Answer 1

Since we are given with the three sides of the triangle and asked to determine the angle, we can use the cosine law.

b² = a² + c² - 2ac(cosB)

Substituting the known values,

(1.8)² = (2.4)² + (1.6)² - 2(2.4)(1.6)(cosB)

The value of B from the equation is 48.6°.

Answer 2

B = 60.6 degree

Explanation:

Side AB, c = 1.2 miles

Side BC, a = 1.8 miles

Side CA, b = 1.6 miles

Use Cosine rule to find the angle B.

`Cos B = (a^(2)+c^(2)-b^(2))/(2ac)`

Putting the values of a, b and c

`Cos B = (1.8^(2)+1.2^(2)-1.6^(2))/(2* 1.8* 1.2)`

`Cos B = (3.24+1.44-2.56)/(4.32)`

`Cos B = 0.491`

B = 60.6 degree