Question

Find the exact values of the six trigonometric functions for angle e in standard position if a point with the coordinates (-6, 6) lies

on its terminal side.
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Note: A value such as = can be entered as sr3/2.

Answer 1

tan e = -1

cot e = -1

sin e = √2/2

cosec e = √2

cos e = -√2/2

sec e = -√2.

Explanation:

6/6- is the tangent of e so tan e = -1.

cot e = 1/tan e = -1.

The hypotenuse of the triangle containing angle e = √(-6)^2 + (6)^2 ( By the pythagoras theorem) and = √72 = 6√2.

Therefore sin e = 6/6√2

= 1/√2

= √2/2

cosec e = 1 ./ sin e = √2.

cos e = -6 / 6√2

= -√2/2.

sec e = 1/cos e = -√2.