Question

How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2

Answer 1

To find the number of grams in 2.3 x 10-4 moles of calcium phosphate (Ca3(PO4)2), you need to calculate the molar mass of calcium phosphate and then convert moles to grams.

Step-by-step explanation:

To find the number of grams in 2.3 x 10-4 moles of calcium phosphate (Ca3(PO4)2), we need to calculate the molar mass of calcium phosphate and then convert moles to grams.

The molar mass of Ca3(PO4)2 can be calculated by adding the atomic masses of calcium (Ca), phosphorus (P), and oxygen (O). The atomic masses are: Ca = 40.078 g/mol, P = 30.973761 g/mol, O = 15.9994 g/mol.

Calculating the molar mass:

• 3Ca: (3 atoms) (40.078 g/mol/atom) = 120.234 g/mol
• 2P: (2 atoms) (30.973761 g/mol/atom) = 61.947522 g/mol
• 8O: (8 atoms) (15.9994 g/mol/atom) = 127.9952 g/mol

Total molar mass of Ca3(PO4)2 = 120.234 g/mol + 61.947522 g/mol + 127.9952 g/mol = 310.176722 g/mol.

Now, we can use the equation:

mass(g) = moles x molar mass(g/mol)

Substituting the given values:

mass(g) = 2.3 x 10-4 moles x 310.176722 g/mol

Calculating the result:

mass(g) = 0.0712 g

Therefore, there are 0.0712 grams in 2.3 x 10-4 moles of calcium phosphate (Ca3(PO4)2).

Answer 2

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain 2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.