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We flip a fair coin 10 times. What is the probability that we get heads in exactly 8 of the 10 flips?

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There are
2^(10) possible outcomes when flipping 10 coins. Of those
{10 \choose 8} have exactly 8 heads. So the probability is


p = \frac{ {10 \choose 8} }{ 2^(10) } = (10(9)/2)/(2^(10))=(45)/(1024)

Answer: 45/1024

User Christopher Chiche
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