Question

Find the product. 3(x + 4) (x - 5) A. 3x2 ? 20x B. 3x2 ? 11x ? 20 C. 3x2 ? 3x ? 60 D. 3x2 ? x ? 20

Answer 1

Step 1: Distribute the 3 to x and 4

(3x + 12)(x - 5)

Step 2: FOIL (First, Outside, Inside, Last)

Multiply the first of the values in the parentheses together

(3x + 12) (x - 5)

`3x^(2)`

Multiply the outside values in the parentheses together

(3x + 12)(x - 5)

-15x

Multiply the inside values of the parentheses together

(3x + 12)(x - 5)

12x

Multiply the last values of the parentheses together

(3x + 12)(x - 5)

-60

Step 3: Add all the FOIL values together

3
`x^(2)` + (-15x) + 12x + (-60)

Step 4: Combine like terms

3
`x^(2)` + (-15x) + 12x + (-60)

3
`x^(2)` - 3x - 60

Hope this helped!

Answer 2

For this case we must find the product of the following expression:
`3 (x + 4) (x-5)`

We must apply distributive property to the terms of the first parenthesis:

`(3x + 12) (x-5) =`

Again we apply the distributive property:

`3x ^ 2-15x + 12x-60 =\\3x ^ 2-3x-60`

ANswer:

`3x ^ 2-3x-60`