Answer:
the diagonals intersect at right angle i.e. slope of AC = - 1/ slope of BD and
Midpoint of AC = Z₁ is equal to Mid point of BD = Z₂
so, the parallelogram is rhombus.
Explanation:
A parallelogram is a rhombus if diagonals intersect each other at right angle and the diagonals intersect at mid point.
We are given vertices:
A(-3,2)
B(-2,6)
C(2,7)
D(1,3)
The diagonals of the parallelogram will be:
AC and BD.
Slope of AC = y₂ - y₁ / x₂- x₁ where A = (-3,2) and C = (2,7)
Putting values:
Slope of AC = 7-2/2-(-3) = 5/5
Slope of AC = 1
Slope of BD = y₂ - y₁ / x₂- x₁ where B = (-2,6) and D = (1,3)
Putting values:
Slope of BD = 3-(6) / 1-(-2) = -3/3
Slope of BD = -1
AS, Slope of AC = - 1/ Slope of BD
So, the diagonals intersect and right angle.
Now finding the mid point Z₁ of AC and Z₂ of BD:
Midpoint of AC = Z₁ = A+C/2
Putting values:
=(-3,2) + (2,7) / 2
= (-1,9)/2
= (-1/2, 9/2)
Mid point of BD = Z₂ = B+D / 2
Putting values:
=(-2,6) + (1,3) / 2
= (-1,9)/2
= (-1/2, 9/2)
Midpoint of AC = Z₁ is equal to Mid point of BD = Z₂ i.e.
Z₁ = Z₂, the diagonals intersect at the same midpoint.
As,
the diagonals intersect at right angle i.e. slope of AC = - 1/ slope of BD and
Midpoint of AC = Z₁ is equal to Mid point of BD = Z₂
so, the parallelogram is rhombus.