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Guys im actually begging please.

Guys im actually begging please.-example-1

1 Answer

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Answer:

sin 2Ф = -24/25

Explanation:

* Lets revise the trigonometry functions in the four quadrants

# First quadrant the measure of all angles is between 0° and 90°

∴ All the angles are acute

∴ All the trigonometry functions of any angle are positive

# Second quadrant the measure of all angles is between 90° and 180°

∴ All the angles are obtuse

∴ The value of sin of any angle is positive (cos and tan are negative)

# Third quadrant the measure of all angles is between 180° and 270°

∴ All the angles are reflex

∴ The value of tan of any angle is positive (sin and cos are negative)

# Fourth quadrant the measure of all angles is between 270° and 360°

∴ All the angles are reflex

∴ The value of cos any angle is positive ( sin and tan are negative)

* We will need to revise two identity to solve the question

# sin²Ф + cos²Ф = 1

# sin 2Ф = 2 sinФ cosФ

* Now lets solve the question

∵ cosФ = 3/5

∵ Ф is in the fourth quadrant

∴ The value of sinФ is negative

∵ sin²Ф + cos²Ф = 1

∴ sin²Ф + (3/5)² = 1

∴ sin²Ф + 9/25 = 1 ⇒ subtract 9/25 from both sides

∴ sin²Ф = 16/25 ⇒ take √ for both sides

∴ sinФ = ± 4/5

- We will chose the value -4/5 because Ф is in the fourth quadrant

∴ sinФ = -4/5

∵ sin 2Ф = 2 sinФ cosФ

∵ sinФ = -4/5 and cosФ = 3/5

∴ sin 2Ф = 2 (-4/5) (3/5) = -24/25

User Jalani
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