Answer:
(-2, -4)
Explanation:
we have
![f(x)=-x^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b0aex82628a8f1nvynoor5q1km8c62ij1z.png)
we know that
If a ordered pair lies on the graph, then the ordered pair must satisfy the equation of f(x)
Verify each ordered pair
case A) (-4, 2)
Substitute the value ox x and the value of y in the equation and then compare the results
![2=-(-4)^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k1stie0g88rzfxx63u5a049n6vaot2frw4.png)
------> is not true
therefore
The point not lies on the graph
case B) (-2, -4)
Substitute the value ox x and the value of y in the equation and then compare the results
![-4=-(-2)^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/anelm2yagtg37iv6egqnhgkiggp38krqiz.png)
------> is true
therefore
The point lies on the graph
case C) (-2, 4)
Substitute the value ox x and the value of y in the equation and then compare the results
![4=-(-2)^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1vsp770iyxs3pt12qktyzwu9qb842pf0zr.png)
------> is not true
therefore
The point not lies on the graph
case D) (4, -2)
Substitute the value ox x and the value of y in the equation and then compare the results
![-2=-(4)^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iay9btdjyzavayrc3qnl832agr5fq8olrk.png)
------> is not true
therefore
The point not lies on the graph