Question

How many liters of a 0.352 M solution of Ca(SO4) would contain 62.1 g of Ca(SO4)?​

Answer 1

1.3 L.

Step-by-step explanation:

• Molarity is the no. of moles of solute per 1.0 L of the solution.

M = (no. of moles of CaSO₄)/(Volume of the solution (L))

M = 0.352 M.

no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,

Volume of the solution = ??? L.

∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))

∴ (Volume of the solution (L) = (0.456 mol)/(0.352 M) = 1.296 L ≅ 1.3 L.