Question

If f(x)=3x2-2 and g(x)=4x+2 what is value of (f+g)(2)

Answer 1

Answer: The required value is 20.

Step-by-step explanation: We are given the following two functions :

`f(x)=3x^2-2,~~~~~~~g(x)=4x+2.`

We are to find the value of (f + g)(2).

We know that, for any two functions p(x) and q(x), we have

`(p+q)(x)=p(x)+q(x).`

So, we have

`(f+g)(x)\\\\=f(x)+g(x)\\\\=3x^2-2+4x+2\\\\=3x^2+4x.`

Therefore, at x = 2, we get

`(f+g)(2)=3*2^2+4*2=12+8=20.`

Thus, the required value is 20.

Answer 2

Answer: -4

`(f + g) (2) = -4`

Explanation:

We have the functions

`F(x) =-3x^2-2` And
`g(x)=4x+2`

We want to find

`(f + g) (x)`

Then

`(f+g)(x) = f(x) + g(x)\\\\(f+g)(x) = -3x^2-2 + 4x+2\\\\(f+g)(x)= -3x^2 +4x`

finally we find

`(f + g) (2)`

`(f + g) (2) = -3(2)^2 + 4(2)\\\\(f + g) (2) = -3*4 + 8\\\\(f + g) (2) = -12+ 8\\\\(f + g) (2) = -4`