Question

Need Help!!! ASAP

A probability model includes P(red) = 2/7 and P(blue) = 3/14 which of the following probabilities could complete the model? Select all that apply.

P(green) = 2/7 P(yellow) = 2/7
P(green) = 3/8 P(yellow) = 1/8
P(green) = 1/4 P(yellow) = 1/4
P(green) = 5/21 P(yellow) = 11/21
P(green) = 3/7 P(yellow) = 1/14

Answer 1

According to the information you provided, a probability model includes P(red) = 2/7 and P(blue) = 3/14. The probabilities that could complete the model are P(green) = 5/21 and P(yellow) = 11/21. This is because the sum of all probabilities in a probability model must equal 1. In this case, 2/7 + 3/14 + 5/21 + 11/21 = 1.

Answer 2

`P(green)+P(yellow)=(3)/(8)+(1)/(8)`

`P(green)+P(yellow)=(1)/(4)+(1)/(4)`

`P(green)+P(yellow)=(3)/(7)+(1)/(14)`

Explanation:

The given probabilities are:

`P(red)=(2)/(7)`

`P(blue)=(3)/(14)`

Their sum is
`P(red)+P(blue)=(2)/(7)+(3)/(14)`

The probabilities that will complete the model should add up to
`(1)/(2)` so that the sum of all probabilities is 1.

`P(green)+P(yellow)=(2)/(7)+(2)/(7)\\e(1)/(2)`

`P(green)+P(yellow)=(3)/(8)+(1)/(8)=(1)/(2)`

`P(green)+P(yellow)=(1)/(4)+(1)/(4)=(1)/(2)`

`P(green)+P(yellow)=(5)/(21)+(11)/(21)\\e(1)/(2)`

`P(green)+P(yellow)=(3)/(7)+(1)/(14)=(1)/(2)`