Question

A light ray in air is incident on an air to glass boundary at an angle of 40 degrees and is refracted in the glass of 25 degrees with the normal. What is the index of refraction of the glass? A. 1.10 B. 1.25 C. 1.33 D. 1.52 HELP PLEASE!!!!!!!!!

Answer 1

D

Step-by-step explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1. So:

1 sin 40° = n sin 25°

n ≈ 1.52