7.6k views
4 votes
How many molecules are present in 385.55g of NO2?

User Trivektor
by
7.5k points

1 Answer

3 votes

Answer:

5.05x10^24 molecules

Step-by-step explanation:

1. Find the total mass of the compound

14 grams+32 grams= 46 grams per mole

2. Find the moles

385.55 g/ 46 g per mol= 8.38 moles

3. Multiply by Avogadro's Number (6.022 x 10^23)

8.38 moles x 6.022 x 10^23= 5.05x10^24 molecules

User Ihor Yanovchyk
by
8.7k points