Question

This circle below is centered at the point (3 -4) and has a radius of length 3. What is its equation

Answer 1

(x-3)2+(y-4)2=9

Explanation:

Answer 2

`(x-3)^2+(y+4)^2=9`

Explanation:

The equation of a circle with center at (h,k) and radius r units is found using:

`(x-h)^2+(y-k)^2=r^2`

The given circle is centered at the (3,-4) and has radius 3 units,

The equation of this circle is obtained by substituting the given values.

This gives us:

`(x-3)^2+(y--4)^2=3^2`

We simplify to get:

`(x-3)^2+(y+4)^2=9`