Question

Lifting a 81-kg barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights, requires what applied force in N to two significant digits?

Answer 1

960 N

Step-by-step explanation:

answer should have two signif digits

a = change in velocity divided by change in time

1 m/s / .5 s = 2 m/s^2

F = ma a = g + 2 m/s^2 = 9.81 + 2 = 11.81 m/s^2

81 kg * 11.81 m/s^2 = 956.61 N = ~ 960 N (two sig digits)

(Please let me know if this is incorrect....I am not SURE )