Answer:
4153
Explanation:
Let the original number be x
First, you subtract 3 from the original number. This removes 3 from the last digit, but leaves a zero there.
Now to remove the zero, you divide by 10.
Finally, to put the 3 at the first position, you add 3000.
Now Moving the last digit, 3, to the first position the number becomes :
![(x-3)/(10)+3000](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u3irb3d2g6u0j1zd35mrrnonhqzavuavr8.png)
We are given that the number will decrease by 738.
A.T.Q
![(x-3)/(10) + 3000 = x-738](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d4x2y8hrm4u0mdlhnv851n81b1ft4c5eob.png)
![(x-3)/(10)= x - 3738](https://img.qammunity.org/2020/formulas/mathematics/middle-school/89jta2g8gao8wnu55zvmi7s3wuuvq2ayn0.png)
![x-3 = 10x - 37380](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qr100juv84vjlsg6uzeqlsyw8y53kf5wnk.png)
![x = 10x - 37377](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zk1eglxc4kuxjuwr36zycomagvj1yakbv0.png)
![-9x = -37377](https://img.qammunity.org/2020/formulas/mathematics/middle-school/shnuhhxn3j9japzydqmodooeqxzr8tdjrv.png)
![x = 4153](https://img.qammunity.org/2020/formulas/mathematics/middle-school/spd5c0fiszm7ql5nd6l2d4b7ezliiq5393.png)
Hence the original 4-digit number is 4153.