472,893 views
44 votes
44 votes
Im pulling my hair out with this problem my calculator simplified it to
(1+/-√(14))/(10)

What am i doing wrong?? :')

Im pulling my hair out with this problem my calculator simplified it to (1+/-√(14))/(10) What-example-1
User Leo Ufimtsev
by
2.8k points

2 Answers

17 votes
17 votes


~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -(5)/(3) \end{cases}

User Oswin Noetzelmann
by
2.5k points
10 votes
10 votes

Answer:

-5/3 and -1

Explanation:

I am not sure what you mistake is, but here is my solution. I hope that it helps. I am sorry that you are frustrated. We have all been there.

Im pulling my hair out with this problem my calculator simplified it to (1+/-√(14))/(10) What-example-1
User Priyashree Bhadra
by
2.7k points