112k views
5 votes
Solve this system of equations by elimination:

8x+9y=48
12x+5y=21

User Soggiorno
by
8.3k points

1 Answer

3 votes

Answer:

Let's solve your system of equations by elimination.

8x+9y=48;12x+5y=21

Steps:

Multiply the first equation by 5,and multiply the second equation by -9.

5(8x+9y=48)

−9(12x+5y=21)

Becomes:

40x+45y=240

−108x−45y=−189

Add these equations to eliminate y:

−68x=51

Then solve−68x=51for x:

−68x /−68 = 51 /−68 (Divide both sides by -68)

x= −3 /4

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+9y=48

Substitute

−3 /4

8x+9y=48:

8( −3 /4 )+9y=48

9y−6=48 (Simplify both sides of the equation)

9y−6+6=48+6 (Add 6 to both sides)

9y=54

9y /9 = 54 /9 (Divide both sides by 9) y=6

Answer: x= −3 /4 and y=6

Hope This Helps! Have A Nice Day!!

User Ellitt
by
7.1k points