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What is the [OH-] of a solution whose pH=12.5
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What is the [OH-] of a solution whose pH=12.5

User Zathrus Writer
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1 Answer

1 vote

Answer:

0.316

Step-by-step explanation:

ph --> H+ --> Oh-

H+ = 10^-ph

= 10^-12.5

= 3.16 x 10^-13

now for oh-

oh - = 1 x 10^-14 / 3.16 x 10^-13

= .0316

User Gukoff
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