Question

What is the solution of log4(2x-6)=2

Answer 1

Answer:
`x=11`

Explanation:

Remembert that, by definition:

`log_b(x)=y` →
`b^y=x`

Then, you can rewrite
`log_4(2x-6)=2` in exponential form:

`4^2=2x-6`

Now you can solve for the variable "x":

Add 6 to both sides of the equation:

`4^2+6=2x-6+6`

`22=2x`

And finally you must divide both sides of the equation by 2, then:

`(22)/(2)=(2x)/(2)\\\\x=11`