Question

If the current in an inductor is doubled, by what factor is the stored energy multiplied?

a. 4
b. 1/4
c. 2
d. 1/2
e. 1

Answer 1

• a. 4

Step-by-step explanation:

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`I_2=2I_1`

`L=\text{const}`

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`\displaystyle (W_2)/(W_1)\; - \;?`

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`\displaystyle \boldsymbol{(W_2)/(W_1)}=((LI_2^2)/(2) )/((LI_1^2)/(2) ) =(I_2^2)/(I_1^2) =\bigg((I_2)/(I_1) \bigg)^2=\bigg((2I_1)/(I_1) \bigg)^2=2^2=\boldsymbol{4}`