Question

What is the energy (in ev) of an x-ray photon that has a wavelength of 2. 4 nm ?

Answer 1

• E=518 eV

Step-by-step explanation:

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λ=2,4 nm = 2,4·10⁻⁹ m

c=3·10⁸ m/s

h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s

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E - ?

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`\displaystyle \boldsymbol{E}=h\\u =h (c)/(\lambda) =4,14\cdot 10^(-15) \; eV\cdot s\cdot \; (3\cdot 10^8\; m/s)/(2,4\cdot 10^(-9)\; m) =517,5\; eV\approx \boldsymbol{518\; eV}`