2 Answers

Lakshay Rohilla · Answer 1 · 2020-09-17T04:09:27+0000

For this case we have that the surface area of the figure is given by the surface area of a cone plus the surface area of a cylinder.

The surface area of a cylinder is given by:

$SA = 2 \pi * r * h + 2 \pi * r ^ 2$

Where:

h: It's the height

A: It's the radio.

Substituting the values:

$SA = 2 \pi * 1 * 3 + 2 \pi * 1 ^ 2\\SA = 6 \pi + 2 \pi * 1\\SA = 8 \pi\\SA = 25.12 \ units ^ 2$

On the other hand, the surface area of a cone is given by:

$SA = \pi * r * s + \pi * r ^ 2$

Where:

A: It's the radio

s: inclination

Substituting the values:

S
$A = \pi * 1 * 6 + \pi * 1 ^ 2\\SA = 6 \pi + \pi\\SA = 7 \pi$

$SA = 21.98 \ units ^ 2$

Thus, the surface area of the figure is:

$47.1 \ units ^ 2$

ANswer:

$47.1 \ units ^ 2$

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