Answer:
option B) f(x)=x^3-6x^2+11x-6
Explanation:
Zeros means the point at which a given function becomes zero for the value of input.
In given case, zeros of f(x) is required at points 1,2 and 3.
Graphically the point on x-axis where the function line intersects the x-axis is the zero of the function i.e. the function value is 0,
hence
f(x)=0 when x=1
x-1=0
f(x)=(x-1)
f(x)=0 when x=2
x-2=0
f(x)=(x-2)
f(x)=0 when x=3
x-3=0
f(x)=(x-3)
Thus f(x)=(x-1)(x-2)(x-3)
Writing the above polynomial in standard form:
f(x)=x^3-6x^2+11x-6 !