Answer:
or
![P (t) = 580 (1.18) ^ t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m44wmjrxi8skogl4g0uazp6fkvf1l0l4hn.png)
Explanation:
There are two models of exponential growth that you can use to predict the population of bacteria after t hours.
I)
![P (t) = pe ^ {rt}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/anx94ytj09o6dzxmkivtb55mwfgt3vtqcm.png)
II)
![P (t) = p (1 + r) ^ t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1h8ijb234hjfozvsaywpz5lk0akm8d7un9.png)
Where
p is the initial population of bacteria
r is the growth rate
t is the time in hours.
In this case we know that:
![p = 580\\\\r = (18)/(100)\\\\r = 0.18](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k9x6sgkuxyz0en6vieznj5jlr48xp1bicb.png)
Then the equations that can be used to predict the population of bacteria after t hours are:
I)
![P (t) = 580e ^ {0.18t}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1fugs99og0yqi2vojczc29mzjz7jjui9oh.png)
II)
![P (t) = 580 (1 + 0.18) ^ t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ojqgm9yhhhqkeaa7tt9tw5whyy3oax1mb0.png)