Answer:
x = ±(√2)/3
Explanation:
For the quadratic ...
ax^2 +bx +c = 0
the quadratic formula gives solutions as ...
x = (-b ±√(b^2-4ac))/(2a)
Comparing your quadratic to the general form above, we find ...
a = 9; b = 0, c = -2
Filling these values into the formula gives ...
x = (-0 ±√(0^2 -4(9)(-2)))/(2·9)
x = ±(√72)/18 = ±(6√2)/18
x = ±(√2)/3