Question

If a = 1,b=2 and c=-3 find
a^b-c b^c-a c^a-b

Answer 1

The value of

`a {}^(b) - c \: b {}^(c) - a \: c {}^(a) - b \:`

is

`\frac { 19}{8}`

Explanation:

Greetings !

`a {}^(b) - c \: b {}^(c) - a \: c {}^(a) - b`

where,

• a=1
• b=2
• c=-3

Thus, substitute these values to the given equation to find the values.

`a {}^(b) - c \: b {}^(c) - a \: c {}^(a) - b ... \: substitute \: \\ given \: values \\ (1) {}^(2) - ( - 3)(2) {}^( - 3) - 1( - 3) {}^(1) - 2 \\ 1 + 3 \: ( (1)/(8) ) - 1( - 3) - 2 \\ 1 + (3)/(8) + 3 - 2 \\ (11)/(8) + 3 - 2 \\ (35)/(8) - 2 \\ (19)/(8) = 2 (3)/(8)`

Hope it helps