Question

a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time it takes for the container to reach the ground

Answer 1

1.43 s

Step-by-step explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

`S=ut + (1)/(2)at^2`

where

u = 0 is the initial vertical speed

t is the time

a= g = 9.8 m/s^2 is the acceleration

since u=0, it can be rewritten as

`S=(1)/(2)gt^2`

And substituting S=10.0 m, we can solve for t, to find the duration of the fall:

`t=\sqrt{(2S)/(g)}=\sqrt{(2(10.0 m))/(9.8 m/s^2)}=1.43 s`