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How much heat energy is absorbed when 41.5g of ice melts at STP? (Picture Attached)

How much heat energy is absorbed when 41.5g of ice melts at STP? (Picture Attached-example-1
User Niksvp
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1 Answer

3 votes

Answer:

= 13.857 kJ

Step-by-step explanation:

The heat required to melt ice from its solid state to water or liquid states without change in temperature is given by the formula;

Heat = mLf ; where m is the mass of ice and Lf is the latent heat of fusion,

The mass of ice in moles = 41.5 g/18 g

= 2.306 moles

Therefore;

Heat = 2.306 moles × 6.009 kJ/mol

= 13.857 kJ

User Perrako
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