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Please help with the verifying.



Please help with the verifying. ​-example-1
User Mayowa
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  • let's solve each trigonometric function alone
  • csc^2(x)=1/sin^2(x)
  • tan^2(x)=sin^2(x)/cos^2(x)
  • if we divide them the result will be=cot^2(x)(and that's the R.H.S)
  • cot^2(x)=cos^2(x)/sin^2(x)
  • and then divide it by sin^2(x)the result will also be =cot^2(x) (and that's the L.H.S)
  • R.H.S=L.H.S
User Wessel Kranenborg
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