Question

An Isosceles triangle has single measures 55,55,and 70. The side across from the 70 angle is 10 inches long. How long are the other sides?

Answer 1

8.717 both the sides

Explanation:

Given:

Let ABC be the given triangle with

angle A= 55

angle B=55

angle C= 70

side across angle C, c= 10 inches

side across angle B, b =?

aide across angle A,a=?

Now using the law of sin to find a and b:

a/sinA=c/sinC

a= (c/sinC)(sinA)

Putting the values:

a= (10/sin70)(sin55)

a= 8.717

As the given triangle is isosceles so side a=b

hence a=b= 8.717 inches !