Answer:
In the attachment
Explanation:
The point-slope form of an equation of a line:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lwv5ftdd36i4idvu50qxfdgwxhdby4wlt5.png)
m - slope
(x₁, y₁) - point
We have the equation:
![y-5=-(2)/(3)(x+9)\\\\y-5=-(2)/(3)(x-(-9))](https://img.qammunity.org/2020/formulas/mathematics/college/ct5sf9rlk3tvn7e7cc6coqm1idedcac6dq.png)
Therefore we have
the slope m = -2/3
and the point (-9, 5)
A slope
![m=(rise)/(run)](https://img.qammunity.org/2020/formulas/mathematics/college/12obc3iumvubzu2spdizrupwt4usaj95jy.png)
rise = -2
run = 3
From the point (-9, 5) ⇒ 2 units down and 3 units to the right.