Question

The area of the indoor sports exhibition is shown below.

What is its perimeter? m ?

What is its area? m2 ?

Answer 1

• 255.40 m
• 3,097.96 m²

Explanation:

First, you need to make these conversions:

(Remember that
`1m=100cm`)

4,000 cm to m:

`(4,000cm)((1m)/(100cm))=40m`

700 cm to m:

`(700cm)((1m)/(100cm))=7m`

You can observe in the figure that it is formed by two rectangles and a semi-circle.

To calculate the perimeter, you need to add the exterior measures of each figure.

Remember that the circumference of a circle is:

`C=2\pi r`

Where "r" is the radius

Therefore, the perimeter is:

`P=34m+7m+10m+40m+10m+68m+33m+((2\pi (17m))/(2)\\P=255.40m`

To find the area of the indoor sports exhibition, you need to add the areas of the rectangles and the area of the semi-circle.

The area of a rectangle can be calculated with:

`A_r=lw`

Where "l" is the lenght and "w" is the width.

The area of a semi-circle can be calculated with:

`A_(sc)=(\pi r^2)/(2)`

Where "r" is the radius.

Then, the area of the indoor sports exhibition is:

`A=(40m)(10m)+(68m)(33m)+(\pi (17m)^2)/(2)\\A=3,097.96m^2`