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What is the product? Assume x ≠ 0. 2x^2/3{6/x} 3x 4x 3x2 4x2

What is the product? Assume x ≠ 0. 2x^2/3{6/x} 3x 4x 3x2 4x2-example-1
User Ivan Ruski
by
7.5k points

2 Answers

2 votes

Answer:

4x

Explanation:


(2x^2)/(3)((6)/(x))

2x^2 can be written as 2*x*x

so the given expression becomes


(2*x*x)/(3)((6)/(x))

we cancel out x at the top and bottom

we know 6 divide by 3 is 2


(2*x)/(1)((2)/(1))

Now we multiply the numerator with numerator and denominator with denominator

4x

User Doron Segal
by
8.8k points
4 votes

Answer:

4x

Explanation:

The given product is;


(2x^2)/(3)((6)/(x))

This is the same as;


(2x^2* 6)/(3* x)

We cancel out the common factors to obtain;


(2x* 2)/(1* 1)

Multiply out to obtain;


(4x)/(1)

Simplify


4x

The second option is the correct choice.

User Violette
by
7.9k points